In Fig. 3.3, the p.d. between A and B will be
The answer is :- 4
24 V is applied across the two series 12 resistors, therefore, current through these
resistors =
24
12+12
= 1 A
P.D. between A and negative terminal of battery = 1 x 12 = 12 V.
24 V is applied across the 3 and 9
resistors iin series,
so current through these resistors =
24
3+9
= 2 A.
P.D. between B and negative terminal of battery = 2 x 9 = 18 V.
A at a potential of 12 V and B at a potential of 18 V with respect to negative battery terminal gives a p.d. between A and B = 18 - 12 = 6 V, with B of greater potential than A.
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