A capacitor has a reactance of 16 when connected to a 50Hz supply. Its capacitance
will be approximately
The answer is :- 1 Xc= 1 / (2 x PI x F x C).
Therefore C = 1 / (2 x PI x F x Xc) = 1 / (2 x PI x 50 x 16) =
approximately 200F
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