A battery has an e.m.f. of 12V and an internal
resistance of 2. The maximum power that can be taken from the
battery is
The answer is :- 1
For maximum power, load resistance equals
internal resistance of battery, i.e. 2.
Total resistance of circuit = 2 + 2 = 4
Current I = 12 / 4 = 3 A.
Power dissipated in load = 32 x 2 = 18 W.
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