Simple alternating current circuits

Explanation of question 12

A capacitor has a reactance of 16 when connected to a 50Hz supply. Its capacitance will be approximately

  1. 200 F
  2. 100 F
  3. 200 pF
  4. 100 pF

The answer is :- 1 Xc= 1 / (2 x PI x F x C).  Therefore C = 1 / (2 x PI x F x Xc) = 1 / (2 x PI x 50 x 16) = approximately 200F

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