If the circuit in Fig. 3.1 (as in the previous
two problems), is connected across a 40V supply, the power
dissipated in the 15 resistor will be
The answer is :- 1
P.D. across 15 resistor = 12 V,
and the current through 15 resistor = 0.8 A,
so power, P = VI = 12 x 0.8 = 9.6 W
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