The answer is :- 4
Assume the resistor as a value of 24 Ohms. I=V/R
At 12v I would be I = 12/24 = 0.5Amps. W = V x I or W= 12 x 0.5 = 6w
At 6v I would be I=6/24 = 0.25Amps. W = V x I or W = 6 x 0.25 =1.5w
1.5w is one-quarter of the original power of 6w
OR:-
P = V2 / R.
R is a constant, therefore, P V2. <
New power will be (½)2 = ¼ of the original power.
R is a
constant, therefore, P V2. <
New power will be (½)2 = ¼ of the original power.
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