A coil has a Q of 150, and is series resonated across a 6V AC supply. The p.d. across the capacitor will be
The answer is :- 4 At resonance, XL and XC will cancel out so that the circuit impedance Z will equal the resistance of the circuit, R. Thus, p.d. across R will equal 6V.
The p.d. across L, VL = VR x Q = 6 x 150 = 900V
There will be an equal (but opposite) voltage developed across the capacitor, i.e. 900V
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