In Fig. 3.4, the p.d. between A and B, and the total power dissipated, will be respectively
The answer is :- 2
All current from the 12 V battery flows through
the lower 1.2 k resistor. No current flows through upper 1.2
k
resistor, so there is no p.d. across the upper
1.2 k
resistor.
Potential at A is the same as the potential of the positive terminal of the battery,
i.e. 12 V, therefore p.d. between A and B = 12 V.
The only power dissipated will be the lower 1.2
k resistor and will be:
P=V2 / R =
12 2
1.2x103
= 144 / 1.2 mW = 120 mW
BACK |
page (tq0311ex) |
Some material Copyright John Bowyer G4KGS. |
Click here for important Copyright information |
Web Space provided by Hostroute.com Ltd |
Contact details |