Resistors in series and parallel; power

Explanation of question 8

If the circuit in Fig. 3.1 (as in the previous two problems), is connected across a 40V supply, the power dissipated in the 15 resistor will be

  1. 9.6W
  2. 21.6W
  3. 56 W
  4. 80W

The answer is :- 1

P.D. across 15 resistor = 12 V,

and the current through 15 resistor = 0.8 A,

so power, P = VI = 12 x 0.8 = 9.6 W

BACK
page (tq0308ex)
Some material Copyright John Bowyer G4KGS.
Click here for important Copyright information
Web Space provided by Hostroute.com Ltd
Contact details