If the circuit in Fig. 3.1 is connected across a
40V supply, the p.d. across the 10 resistor will be
The answer is :- 4
Total resistance = 20
Total current = total p.d. / total resistance = 40 / 20 = 2 A
P.D. across 14 resistor = 2 x 14 = 28 V,
so p.d. across the parallel combination = 40 - 28 = 12 V,
i.e. the p.d. acrross both the 10 and 15
resistors.
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