Multiples and sub-multiples, abbreviations and indices

Explanation of question 12

A 12k resistor has a p.d. of 24mV applied across its terminals. The current through the resistor will be

  1. 0.5mA
  2. 0.5 A
  3. 2 mA
  4. 2 A

The answer is :- 4

I =

= 24 x 10-3
12 x 103

= 2 x 10-3
103

= 2 x 10-3 x 10-3

= 2 x 10-6 A

= 2A

BACK
page (tq0212ex)
Some material Copyright John Bowyer G4KGS.
Click here for important Copyright information
Web Space provided by Hostroute.com Ltd
Contact details