Resonance and its applications

Explanation of question 11

11 A parallel resonant circuit has a coil of inductance 800mH and resistance 8 in parallel with a 5F capacitor. The dynamic resistance will be

  1. 200k
  2. 160k
  3. 20k
  4. 20

The answer is :-

Dynamic resistance =

= 800x10-3 ÷ 40x10-6 

= 20,000 = 20k

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